A gas in a sealed container had its volume increased from 12.1 liters to 21.1 liters.
and heated from 241 K to 298 K. If the original pressure was 546 torn what would
be the final pressure in torr?

The answer to your question is   P2 = 170.9 torr

Explanation:

Data

Volume 1 = 12.1 l                                Volume 2 = 21.1 l

Temperature 1 = 241 °K                      Temperature 2 = 298°K

Pressure 1 = 546 torr                           Pressure 2 = ?

Process

To solve this problem use the combined gas law.

                P1V1/T1 = P2V2/T2

-Solve for P2

                P2 = T1V1T2 / T1V2

-Substitution

                P2 = (241 x 12.1 x 298) / (241 x 21.1)

-Simplification

                P2 = 868997.8 / 5085.1

-Result

                P2 = 170.9 torr

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.