PLEASE HELP
What is the molarity of a solution of sucrose, C12H22O11, that contains 125 g of
sucrose in 3.50 L of solution/ Please show your work.

The answer to your question is 0.10 M

Explanation:

Data

Molarity = ?

mass of Sucrose = 125 g

volume = 3.5 l

Formula

Molarity = moles / volume

Process

1.- Calculate the molar mass of sucrose

C₁₂H₂₂O₁₁ = (12 x 12) + (1 x 22) + (16 x 11)

               = 144 + 22 + 176

               = 342 g

2.- Convert the mass of sucrose to moles

                  342 g of sucrose 1 mol

                  125 g of sucrose x

                           x = (125 x 1) / 342

                           x = 0.365 moles

3.- Calculate the molarity

Molarity = 0.365 / 3.5

4.- Result

Molarity = 0.10

im not exactly sure but i think its b!

може ли да зареждате повече информация, моля