When the volume is 2.35 L and the temperature is 122oC, the pressure is 1.78 atm. What is the new pressure if the volume is decreased to 1.15 L and the gas is cooled to 14.0oC?

The answer to your question is  P2 = 2.64 atm

Explanation:

Data

Volume 1 = 2.35 L

Temperature 1 = 122°C

Pressure 1 = 1.78 atm

Volume 2 = 1.15 L

Temperature 2 = 14°C

Pressure 2 = ?

Process

To solve this problem use the combined gas law.

                     P1V1/T1 = P2V2/T2

-Solve for P2

                      P2 = P1V1T2/T1V2

1.- Convert temperature to °K

Temperature 1 = 122 + 273 = 395°K

Temperature 2 = 14 + 273 = 287°K

2.- Substitution

                     P2 = (1.78 x 2.35 x 287) / (395 x 1.15)

3.- Simplification

                      P2 = 1200.521 / 454.25

4.- Result

                      P2 = 2.64 atm

2b2t

explanation:

2b2t