2A1 + 3MgCl2 --> 2AlCl3 + 3Mg
How many moles of aluminum chloride are produced from 2.5 moles of magnesium
chloride?

The answer to your question is 1.67 moles

Explanation:

Data

moles of AlCl₃ = ?

moles of MgCl₂ = 2.5

Balanced chemical reaction

                 2Al  +  3MgCl₂  ⇒   2AlCl₃  +  3Mg

Process

To solve this problem using proportions and cross multiplication.

Use the coefficients of the balanced chemical reaction.

                    3 moles of MgCl₂ 2 moles of AlCl₃

                    2.5 moles of MgCl₂  x

                                     x = (2.5 x 2) / 3

-Simplification

                                    x = 5 / 3

-Result

                                    x = 1.67 moles