Calculate the molarity of 13.1 g of NaCl in 727 mL of solution

The molarity of the solution is 0,31 M

Explanation:

We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)

Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g

58, 5 g1 mol NaCl

13,1 g x= (13,1 g x 1 mol NaCl)/58, 5 g= 0, 224 mol NaCl

727 ml solution 0, 224 mol NaCl

1000ml solutionx= (1000ml solutionx0, 224 mol NaCl)/727 ml solution

x=0,308 mol NaCl---> The solution is 0,31 molar (0,31 M)

6.4 cm (max) - 25 cm (min)

2b2t

explanation:

2b2t