Calculate the molarity of a solution that contains 15.7 g of CaCO3 dissolved in enough water to make 275 mL of solution.

Molarity= 0.57M

Explanation:

m=15.7 Molar mass Of CaCO3= 100 V=0.275dm3 C=?

n= m/M = 15.7/100= 0.157mole

n= C×V

0.157= C× 0.275

C= 0.57M

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