10. A sample of a hydrocarbon was analyzed and found to contain 12.59g of carbon and 1.41g of hydrogen a the empirical formula of the compound. (As the masses are known you do not need to assume you have a 100

The answer to your question is C₃ H₄

Explanation:

Data

mass of Carbon = 12.59 g

mass of Hydrogen = 1.41 g

Process

1.- Convert the mass to moles

-Carbon

Atomic mass = 12 g

                                12 g of C 1 mol

                                 12.59 g of C x

                                  x = (12.59 x 1) / 12

                                  x = 1.05 moles of C

-Hydrogen

Atomic mass = 1.008

                               1.008 g of H 1 mol

                                1.41 g of H     x

                                 x = (1.41 x 1) / 1.008

                                 x = 1.399 moles of H

2.- Divide by the lowest number of moles

Hydrogen = 1.399/1.05 = 1.33

Carbon = 1.05/1.05 = 1

3.- Write the empirical formula

                                  C₁ H ₁.₃₃ ≈  3 x C₁ H ₁.₃₃  = C₃ H₄

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.