How many moles of CO2 will be produced from 97g of C3H8 assuming O2 is available in excess

6.6 moles

Explanation:

Given data:

Moles of CO₂ produced = ?

Mass of C₃H₈ react = 97 g

Solution:

Chemical equation:

C₃H₈ + 5O₂    →   3CO₂ + 4H₂O

Number of moles of C₃H₈:

Number of moles = mass/ molar mass

Number of moles = 97 g/ 44.1 g/mol

Number of moles = 2.2 mol

Now we will compare the moles of C₃H₈ with CO₂  from balance chemical equation.

                 C₃H₈             :              CO₂

                    1                 :                  3

                   2.2              :               3 ×2.2=6.6

Thus from 97 g of C₃H₈  6.6 moles of  CO₂ are produced.

precipitation

explanation:

when it goes from cloud to rain/back to earth in the form of rain

6.4 cm (max) - 25 cm (min)