If 200.0 dm3 (L) of propane are burned at STP, what volume of carbon dioxide is formed at STP? C3H8 + O2 CO2 + H2O

604.13L

Explanation:

Given parameters:

Volume of propane = 200dm³ or 200L

Unknown:

Volume of carbon dioxide formed  = ?

Solution:

The reaction equation is given as;

                       C₃H₈    +   5O₂      →      3CO₂     +      4H₂O

The above is the balanced reaction equation.

Let us solve from the known to the unknown;

   The known here is propane and unknown is carbon dioxide

At STP;

              Number of moles of propane  =   =     = 8.93moles

From the balanced reaction equation;

          1 mole of propane gives 3 moles of carbon dioxide;

        8.93 moles of propane will produce;  3 x 8.93  = 26.97moles

Now,

    Volume of carbon dioxide  = number of moles x 22.4

                                                   = 26.97 x 22.4

                                                    = 604.13L

14 days is the half-life of phosphorus-32