6) What quantity of ice at 0°C will be melted by 6.8 x 10^ J of energy?

0.02kg

Explanation:

Given parameters:

Temperature of ice  = 0°C

Energy  = 6.8 x 10³J(let us assume it is 10³)

Unknown:

Mass of ice melted  = ?

Solution:

This problem deals with a change of state physical change. The ice changes to water at the same temperature.

Heat changes accompanying such reactions is given by;

             H  = mL

where m is the mass

           L is the heat of vaporization

For water L  = 3.3×10⁵ joule/kg

           Since m is the unknown; we can solve for it;

                         m  =   = 0.02kg

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.