6) What quantity of ice at 0°C will be melted by 6.8 x 10^ J of energy?

0.02kg

Explanation:

Given parameters:

Temperature of ice  = 0°C

Energy  = 6.8 x 10³J(let us assume it is 10³)

Unknown:

Mass of ice melted  = ?

Solution:

This problem deals with a change of state physical change. The ice changes to water at the same temperature.

Heat changes accompanying such reactions is given by;

             H  = mL

where m is the mass

           L is the heat of vaporization

For water L  = 3.3×10⁵ joule/kg

           Since m is the unknown; we can solve for it;

                         m  =   = 0.02kg

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