What is the concentration of FeCl3 in a solution prepared by dissolving 10.0 g of FeCl3 in enough water to make 275 mL of solution?What is the concentration of FeCl3 in a solution prepared by dissolving 10.0 g of FeCl3 in enough water to make 275 mL of solution?0.224 M4.46 × 103 M4.46 M2.24 × 10-4 M

The concentration of FeCl₃ in the solution is 0.224M. The correct option is the first option - 0.224 M

First, we will determine the number of moles of FeCl₃ present in the solution

Mass of FeCl₃ = 10.0 g

Using the formula

Molar mass FeCl₃ = 162.204 g/mol

∴ Number of moles of FeCl₃ present =

Number of moles of FeCl₃ present = 0.06165 mole

Now,

For the concentration of FeCl₃ in the solution

From the formula

Volume of the solution = 275 mL = 0.275 L

∴ Concentration of FeCl₃ in the solution =

Concentration of FeCl₃ in the solution = 0.224 M

Hence, the concentration of FeCl₃ in the solution is 0.224M. The correct option is the first option - 0.224 M

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The concentartion of solution will be 0.224 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

where,

n= moles of solute =

= volume of solution in ml = 275 ml

Now put all the given values in the formula of molarity, we get

Therefore, the concentration of solution will be 0.224 M

the answer is b. dilution