How much ice in grams would have to melt to lower the temperature of 360 mL of water from 45 ∘C to 0 ∘C? (Assume that the density of water is 1.0 g/mL.) Express your answer using two significant figures.

Answer

203.7g

Explanation:

Heat gained= - heat lost

From the question

Mass of water = 360g

Heat capacity of water= 4.2Jg-1

Latent heat of ice= 334Jg-1

ml= -mcθ

m×334= -(360×4.2×(0-45))

334m= 68040

m= 68040/334

=203.7g

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.