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Chemistry, 08.04.2020 01:53 cathydaves

The dissociation of calcium carbonate has an equilibrium constant of Kp = 1.16 at 1073 K . CaCO3(s) ⇄ CaO(s) + CO2(g) If you place 35.9 g of CaCO3 in a 9.56-L container at 1073 K, what is the pressure of CO2 in the container?

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The dissociation of calcium carbonate has an equilibrium constant of Kp = 1.16 at 1073 K . CaCO3(s)...
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