Use the law of constant composition to complete the following table summarizing the amounts of iron and chlorine produced upon the decomposition of the sample of iron(iii) chloride. mass fecl3 mass fe mass cl sample a3.785 g1.302 g2.483 g sample b1.475 g

Answer : The mass of Fe and Cl in sample B is 3.341 g and 6.371 g respectively.

Explanation :

Law of definite proportion : It is defined as a given compound always contains exactly the same proportion of elements by weight.

The balanced chemical reaction will be,

First we have to calculate the ratio of mass of .

Now we have to calculate the mass of Fe and Cl in sample B.

and,

Therefore, the mass of Fe and Cl in sample B is 3.341 g and 6.371 g respectively.

ljjjljlj kjlk,ljym jlyu; jm; l mumytj

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.