G An arctic weather balloon is filled with 31.0 L of helium gas inside a prep shed. The temperature inside the shed is 7. C. The balloon is then taken outside, where the temperature is -35. C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Be sure your answer has the correct number of significant digits.

The new volume at at temperature of -35 °C is 26.4 L

Explanation:

Step 1: Data given

Volume of the helium gas inside a prep shed = 31.0 L

The temperature inside the shed is 7.0 °C = 7+273 = 280 K

The balloon is then taken outside, where the temperature is -35. C = 273 -35 = 238K

The pressure on the balloon stays constant at exactly 1 atm

Step 2: Calculate the new volume

V1/T1 = V2/T2o

⇒with V1 = the original volume of the helium gas inside a prep shed = 31.0 L

⇒with T1 = the original temperature inside the shed = 280 K

⇒with V2 = the new volume of the helium gas inside a prep shed = TO BE DETERMINED

⇒with T2 = the decreased temperature = 238 K

31.0 L / 280 K = V2 / 238 K

V2 = (31.0L / 280K) * 238 K

V2 = 26.35 ≈ 26.4 L

The new volume at at temperature of -35 °C is 26.4 L

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2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.