A titration reached the equivalence point when 17.0 mL of was added to of NaOH (aq) of unknown concentration. What is the concentration (M) of this unknown NaOH solution? H2SO4(aq) + 2NaOH(aq) → Na2SO4(aq) + 2H2O(l)

This is an incomplete question, here is a complete question.

A titration reached the equivalence point when 17.0 mL of 0.211 M H₂SO₄ (aq) was added to 16.3 mL of NaOH (aq)  of unknown concentration. What is the concentration (M) of this unknown NaOH solution?

Answer : The concentration (M) of this unknown NaOH solution is, 0.440 M

Explanation :

To calculate the concentration of unknown NaOH solution, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is

are the n-factor, molarity and volume of base which is NaOH.

We are given:

Now put all the given values in above equation, we get:

Therefore, the concentration (M) of this unknown NaOH solution is, 0.440 M

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )