The equilibrium constant Kc for the reaction PCl3(g) + Cl2(g) PCl5(g) is 49 at 230°C. If 0.70 mol of PCl3 is added to 0.70 mol of Cl2 in a 1.00-L reaction vessel at 230°C, what is the concentration of PCl3 when equilibrium has been established?

Concentration of PCl₅ at equilibrium = 24.01 mole/lit

Explanation:

Given

    Equilibrium constant  Kc = 49

                      PCl₃ (g) + Cl₂(g) ⇄ PCl₅(g)

According to Law of Mass action

Given that

Concentration of PCl₃ = 0.7 mole/lit & conc. of Cl₂ = 0.7 mole/lit

∴ volume of the vessel constant = 1 lit

    ∴ Concentration of PCl₅ at equilibrium = 49 x 0.7 x 0.7 = 24.01

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.