How much heat is absorbed/released when 20.00 g of NH3(g) (17.0307g/mol) react in the presence of excess O2(g) to produce NO(g) and H2O(l) according to the following chemical equation? 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l) ΔH° = 1168 kJ

342.8 kJ are absorbed

Explanation:

In the reaction:

4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l) ΔH° = 1168 kJ

As ΔH > 0, the heat is absorbed. Also, when 4 moles of NH3 are involved in the reaction, there are absorbed 1168 kJ.

Having this in mind, moles of NH3 in 20.00g are:

20.00g × (1mol / 17.0307g) = 1.174 moles

Thus, 1.174 moles of NH3 absorbed:

1.174 moles × (1168 kJ / 4 moles) = 342.8 kJ are absorbed.

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

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chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.