What is the mole fraction of a nonelectrolyte in an aqueous solution above which the vapor pressure of water is 745 mm hg at 100°c?

Mole fraction of the nonelectrolyte is 0.020

Explanation:

To solve this question you need to use Raoult's law that states vapor pressure of a solvent above a solution is equal to the vapor pressure of the pure solvent times mole fraction of the solvent present. The formula is:

Where the pressure of the solution is 745mm Hg, X is mole fraction of the solvent and P° is the pressure of the pure solvent (760mm Hg). Replacing:

745 mmHg = X 760 mmHg

0.980 = X

In an aqueous solution of a nonelectrolyte, the mole fraction of water + mole fraction of nonelectrolyte = 1. As mole fraction of water is 0.980:

1 = 0.980 + Y -Where Y is mole fraction of nonelectrolyte.-

Y = 0.020

I hope it helps!

what are the two models

explanation: