If 25 g of NH3, and 96 g of H2S react according to the following reaction, what is the
maximum mass of ammonium sulfide that can be formed?

2 NH3 + H2S > (NH4)2S

25 g of NH₃ will produce 47.8 g of (NH₄)₂S

Explanation:

2 NH₃ + H₂S ----> (NH₄)₂S

Molecular weight of NH₃ = 17 g/mol

Molecular weight of (NH₄)₂S = 68 g/mol

According to the balanced reaction:

2 X 17 g of NH₃ produces 68 g of (NH₄)₂S

1 g of NH₃ will produce g of (NH₄)₂S

25g of NH₃ will produce of (NH₄)₂S

                                     = 47.8 g of (NH₄)₂S

Therefore, 25 g of NH₃ will produce 47.8 g of (NH₄)₂S

i dont know

explanation:

"the periodic table is arranged in order of atomic number."