The temperature of 300 milliliters of a gas at 400K is increased to 800K, pressure remaining constant. What will the new volume of gas be?

V₂ = 600 mL

Explanation:

Given data:

Initial volume = 300 mL

Initial temperature = 400 K

Final temperature = 800 K

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 300 mL × 800 K / 400 k

V₂ = 240000 mL.K / 400  K

V₂ = 600 mL

the dependant variable is spilled water

the independent is the heat

aquifers are bounded above and below by impermeable rock. the driving force of groundwater movement in confined aquifers is pressure, rather than gravity.