What is the mass of 0.12 mol of mg(no3)2?
show your work.

17.796 g

Explanation: Molar masses of the given elements:

mMg= 24.3 g/mol

mN=14 g/mol

mO=16 g/mol

molar mass of Mg(NO3)2:

mMg(NO3)2= 24.3+(14+3*16)*2

mMg(NO3)2=148.3 g/mol

To calculate the mass of 0.12 mol of Mg(NO3)2 we multiply the molar mass by the number of moles:

mass=0.12mol*148.3 g/mol

mass=17.796 g

the ratio of the conjugate base to the acid required to attain the desired ph.

level 4 to level 2 : ))