How many moles of Ag will be produced from 16g of Cu, assuming AgNO3 is available in excess

Assuming the reaction you are referring to is the following:

AgNO3 + Cu --> Cu(NO3)2 + Ag

First, we should balance the reaction:

2 AgNO3 + Cu --> Cu(NO3)2 + 2 Ag

Now we carry out dimensional analysis, taking into account the molar ratios of different species as given in the balanced reaction and molar masses (which we can look up in the periodic table).

We begin with what we know, which is that we have 16.0 g Cu reacting and work our way toward the quantity that we would like to calculate, namely moles of Ag.

16.0 g Cu x   1 mol Cu    x   2 mol Ag    = 0.504 mol Ag

                     63.5 g Cu       1 mol Cu

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

3 1/4 %

explanation: