In a laboratory 0.500 moles of NAOH is completely dissolved in distilled water to form 400.0 mL of NAOH. The solution is then used to titrate a solution of HNO3.

Which answer choice correctly completes the equation by filling in the formulas of the products in this titration reaction?

NaOH(aq) + HNO3(aq) —> —————- + —————-

1: NaNO2(aq) + H2O2(L)

2: NaNO3(aq) + H2O(L)

3: HNaNO3(aq) + OH(L)

4:H2NO3(aq) + NaO(L)

The answer to your question is number 2.  NaNO₃   +       H₂O

Explanation:

The reaction that is represented in this problem is an acid-base reaction. An acid-base reaction is a double displacement reaction.

The cation of a reactant attaches to the anion of the other reactant and viceversa.

Reactants      NaOH  and    HNO₃

Cations          Na⁺                 H⁺

Anions          OH⁻                NO₃⁻

Following the previous rule

Products       NaNO₃   +       H₂O

The products are a salt and water.

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

what is the question here. i think you messed up.