The volume of a gas is 27.5 ml at 22*C and 0.974 atm. What will be the volume if the temperature decreases to 15*C and the pressure increases to 0.993 atm?

26.33mL

Explanation:

In solving this question, we apply the general gas equation

(P1×V1)/T1 = (P2×V2)/T2

P1= initial pressure of the gas=0.974atm

V1= intial volume the gas occupies =27.5mL

T1=initial temperature of the gas =22°C =22+273K=295K

P2 = Final pressure of the gas = 0.993atm

V2= final volume of the gas = ?

T2 = final temperature of the gas = 15°C = 15+273=288K

From (P1×V1)/T1 = (P2×V2)/T2, we make V2 subject of formula

V2=(P1×V1×T2)/(P2×T2)

We substitute the given values

V2=(0.974×27.5×288)/(0.993×295)

V2=7714.08/292.935

V2=26.33mL

the dissolution of polymer can be thermodynamically described in 2 steps.