Calculate the concentration of so42â ions in a 0.010 m aqueous solution of sulfuric acid.

The concentration of sulfate ions in the solution is 0.010 M

Explanation:

The chemical formula of sulfuric acid solution is

We are given:

Concentration of sulfuric acid = 0.010 M

The chemical equation for the ionization of sulfuric acid follows:

1 mole of sulfuric acid produces 2 moles of hydrogen ions and 1 mole of sulfate ions

Concentration of sulfate ions = (1 × 0.010) = 0.010 M

Hence, the concentration of sulfate ions in the solution is 0.010 M

answer: c. the experiment shows that the red substance experienced a chemical change.

explanation: chemical change is the change in which chemical composition of the substance changes. physical change is the change in which there is no change in chemical composition.

chemical changes are accompanied by following changes:

a) precipitate formation

b) energy is released or absorbed

c) formation of bubbles

d) change in color

as it is given that the red color has disappeared and there is production of gas, it means the red substance has undergone a chemical change.

e

i think its 5049.

i hope this !