A tire at 21°C has a pressure of 0.82 atm. Its temperature decreases to -3.5°C. If there is no volume
is the pressure after the temperature change?
Use T - TO
0.75 atm
0.89 atm
1.1 atm
1.3 atm

0.75 atm. First option.

Explanation:

First of all, we convert the T° from C to K

21°C + 273 = 294K

-3.5°C + 273 = 269.5K

When the number of moles and the volume remain constant, we can propose this situation:

P₁ / T₁ = P₂ / T₂

The relation states a directly proportion

T° decreases → Pressure decreases

T° increases → Pressure increases

0.82 atm / 294K = P₂ / 269.5K

(0.82 atm / 294K) . 269.5K = P₂ → 0.75 atm

b false

"the periodic table is arranged in order of atomic number."