Chemistry, 01.04.2020 01:11 sammybrain

For the chemical reaction, Li + NaCl <-- --> Na + LiCl, the rate law would be...

A. Rate = k[Li][NaCl]
B. Rate = k[Na] [LiCl]
C. Rate = k[Li] + [NaCl]
D. Rate = k[Na] + [LiCl]

Answers: 3

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For the chemical reaction, Li + NaCl <-- --> Na + LiCl, the rate law would be... A. Rate = k[Li][NaCl] B. Rate = k[Na] [LiCl] C. Rate = k[Li] + [NaCl] D. Rate = k[Na] + [LiCl]

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Another question on Chemistry

For the chemical reaction, Li + NaCl <-- --> Na + LiCl, the rate law would be...

A. Rate = k[Li][NaCl]
B. Rate = k[Na] [LiCl]
C. Rate = k[Li] + [NaCl]
D. Rate = k[Na] + [LiCl]