PLEASE ANSWER ASAP AND SHOW WORK: A camping stove uses a 5.0 L propane tank that holds 68.0 moles of liquid C3H8. How large a container would be needed to hold the same amount pf propane as a gas at 25.0 ⁰C and a pressure of 3.0 atm?

The volume of the container needed is 554.6 L

Explanation:

To calculate the volume of the gas, we use the equation given by ideal gas which follows:

where,

P = pressure of the gas = 3.0 atm

V = Volume of the gas = ? L

T = Temperature of the gas =

R = Gas constant =

n = number of moles of propane gas = 68.0 moles

Putting values in above equation, we get:

Hence, the volume of the container needed is 554.6 L

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explanation:

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