Given the following acids and their Ka values: Phenol, C6H5OH Ka = 1.00 × 10-10 Acetic acid, CH3CO2H Ka = 1.80 × 10-5 Nitrous acid, HNO2 Ka = 4.50 × 10-4 What is the order of increasing base strength for C6H5O−, CH3COO−, and NO2−? Group of answer choices

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Explanation:

value is a measure of acidic strength. The larger the value, the stronger is the acid and the weaker is the conjugate base.

The given values are as follows -

Phenol =

Acetic acid =

Nitrous acid =

Order of increasing acid strength will be -

Phenol < Acetic acid < Nitrous acid

Strongest acid will have weakest conjugate base so the order of increasing base strength will be -

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14 days is the half-life of phosphorus-32

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