How many moles of \ce{CO2}COX
2


will be produced from 72.0 \text{ g}72.0 g72, point, 0, start text, space, g, end text of \ce{CH4}CHX
4


assuming \ce{O2}OX
2


is available in excess?

4.5 moles of carbon dioxide

Explanation:

Given parameters:

Mass of CH₄   = 72g

Unknown:

number of moles of CO₂ produced  = ?

Solution:

To solve this problem, let us write the reaction equation first;

            CH₄     +    2O₂     →    CO₂    +   2H₂O

Now we know that O₂ is in excess and CH₄ is the limiting reactant that will determine the extent of the reaction.

Let us find the number of moles of   CH₄ ;

                Number of moles  =

                                  molar mass of  CH₄ = 12 + 4  = 16g/mol

              Number of moles  =   = 4.5moles

From the reaction equation;

                     1 mole of methane produced 1 mole of carbon dioxide

       4.5 moles of methane will produce 4.5 moles of carbon dioxide