A chemist determined by measurements that 0.015 moles of gold participated in a chemical reaction. Calculate the mass of gold that participated in the chemical reaction. Round your answer to significant digits.

The mass of gold participated in the chemical reaction is 2.95 grams

Explanation:

To calculate the number of moles, we use the equation:

Molar mass of gold = 197 g/mol

Moles of gold participated in the reaction = 0.015 moles

Putting values in above equation, we get:

Hence, the mass of gold participated in the chemical reaction is 2.95 grams

mg3n2 is known as magnesium nitride

explanation:

i don't think ke is an compound

most historians agree that gabriel mouton, the vicar of st. paul’s church in lyons, france, is the “founding father” of the metric system. he proposed a decimal system of measurement in 1670. mouton based it on the length of one minute of arc of a great circle of the earth (now called a nautical mile, 1852 meters). he also proposed the swing-length of a pendulum with a frequency of one beat per second as the unit of length (about 25 cm). a pendulum beating with this length would have been fairly easy to produce, thus facilitating the widespread distribution of uniform standards. over the years, his work was revised, improved, and extended by a number of french scientists.

the political sponsor of weights and measures reform in the french revolutionary national assembly was the bishop of autun, better known as talleyrand. under his auspices, the french academy appointed several committees to carry out the work of developing a usable system of weights and measures for france. one of the committees recommended a decimalized measurement system based upon a length equal to one ten-millionth of the length of a quadrant of the earth’s meridian (i.e., one ten-millionth of the distance between the equator and the north pole).