The lab just ran out of 1 M HCl that you need to complete the Benzillic Acid lab. The TA tells you there is 12 M HCl in the fume hood. You need to make 10.0 mL of 1.0 M HCl. What volume or 12 M HCl will you need to dilute to get the correct volume and concentration of 1.0 M HCl?

0.83 mL

Explanation:

Given data

We can calculate the initial volume of HCl using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 1.0 M × 10.0 mL / 12 M

V₁ = 0.83 mL

The required volume of the initial solution is 0.83 mL.

2b2t

explanation:

2b2t

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