Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 3.4 g of hexane is mixed with 22.6 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to significant digits.

The mass of carbon dioxide that can be produced is 10.3 grams

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of hexane = 3.4 g

Molar mass of hexane = 86.2 g/mol

Putting values in equation 1, we get:

Given mass of oxygen gas = 22.6 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

The chemical equation for the reaction of hexane and oxygen gas follows:

By Stoichiometry of the reaction:

2 moles of hexane reacts with 19 moles of oxygen gas

So, 0.039 moles of hexane will react with = of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, hexane is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of hexane produces 12 moles of carbon dioxide

So, 0.039 moles of hexane will produce = of carbon dioxide

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 0.234 moles

Putting values in equation 1, we get:

Hence, the mass of carbon dioxide that can be produced is 10.3 grams