A solution of carbon tetrachloride and carbon disulfide containing 50% by weight of each is to be continuously distilled at a rate of 5000 kg/h.
(a) Determine the concentration of the mixture in terms of mole fractions. (b) Determine the average molecular weight of the mixture.
(c) Calculate the feed rate in kmol/h.

(a) CS₂ = 0.331, CCl₄ = 0.669; (b) 102 g/mol; (c) 49.1 kmol/h

Explanation:

Assume 5000 kg of mixture.

(a) Mole fractions

(i) Mass of each compound

Mass of CCl₄ = 2500 kg

Mass of CS₂ = 2500 kg

(ii) Moles of each compound

(iii) Mole fractions

Total moles = 16.3 kmol + 32.8 kmol = 49.1 kmol

The major component is usually called the solvent — Component 1 —carbon disulfide.

(c) Average molar mass

The average molar mass is the weighted molar mass of each component.

(d) Feed rate

i would wait to see what he says back. then if he likes you back that's great go for it. if he doesn't than hopefully you can stay friends. if not i'm sure he's the one missing out.

explanation: