A gas storage tank has a volume of 3.5 x 10^5 m^3 when the temperature is 27 C and the pressure is 101 kPa. What os the new volume of the tank if the temperature drops to -10 C and the pressure drops to 95 kPa

3.26×10⁵m³

Explanation:

Given data:

Initial volume = 3.5×10⁵ m³

Initial temperature = 27 °C

Initial pressure = 101 Kpa

Final temperature = -10°C

Final pressure = 95 Kpa

Final volume = ?

Solution:

Initial temperature = 27 °C (27+273= 300 K)

Final temperature = -10°C (-10+273 = 263 K)

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 101 Kpa × 3.5×10⁵ m³× 263 K / 300 K× 95 Kpa  

V₂ = 92970.5 ×10⁵ kpa.m³. K / 28500 K. Kpa

V₂ = 3.26×10⁵m³

away from the curb

explanation:

the wheels would then hit the curb if it started to rolling, decreasing the chance of an accident.