3.80 moles of oxygen are used up in the reaction. How many moles of water are produced?5.How many grams of oxygen does it take to produce 9.60 moles of carbon dioxide?6.How many moles of carbon dioxide are produced with using 5.80 grams of acetylene?7.How many grams of oxygen are required to burn 13.50 grams of acetylene?

2 KClO3 (s) = 2 KCl (s) + 3 O2 (g)

2.5 g x g

Explanation:

x g O2 = 2.5 g KClO3 x (1 mol KClO3) x (3 mol O2) x (32 g O2) = 0.98 g O2

(122.5 g KClO3) (2 mol KClO3) (1 mol O2)

2 KClO3 (s) 2 KCl (s) + 3 O2 (g)

2.5 g x g

x g KCl = 2.5 g KClO3 x (1 mol KClO3) x (2 mol KClO3) x (74.5 g KCl) = 1.52 g KCl

(122.5 g KClO3) (2 mol KClO3) (1 mol KCl)

2 KClO3 (s) 2 KCl (s) + 3 O2 (g)

x mol 10 mol

x mol KClO3 = 10 mol O2 x (2 mol KClO3) = 6.7 mol KClO3

(3 mol O2)

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-