How many molecules are in 3.55 miles of Aluminum Sulphate

2.14 x 10^24 molecules

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms

So, 1 mole of ammonium sulphate = 6.02 x 10^23 molecules

3.55 moles of Aluminum Sulphate = Z molecules

To get the value of Z, cross multiply:

Z molecules x 1 mole = (6.02 x 10^23 molecules x 3.55 moles)

Z = 21.37 x 10^23 molecules

Z = 2.137 x 10^24 molecules (to 3 decimal place)

Rounded to nearest hundredth Z becomes 2.14 x 10^24

Thus, there are 2.14 x 10^24 molecules in 3.55 miles of Aluminum Sulphate.

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

hope this

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.