What is the molality if 734 mol of lithium sulfate are dissolved to make
2500 kg of solution.

a) 0.59
b) 0.29
c) 293.6
d) 29.4

0.29 M

Explanation:

We are given;

We are needed to determine the molarity of lithium sulfate solution.

We need to know that;

Molarity of a solution = Moles of the solute ÷ Volume of the solution

Taking the density of the solution to be 1 000 kg/m³ or 1 g/cm³

Then;

Volume = Mass ÷ density

             = 2500 kg ÷ 1000 kg/m³

             = 2.5 m³

But, 1 m³ = 1000 L

Thus, volume = 2500 L

Therefore;

Molarity = 734 mol ÷ 2500 L

             = 0.2936 mol/L

             = 0.29 M

Therefore, the molarity of lithium sulfate solution is 0.29 M

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

am i too late?

explanation: