Lithium reacts with lead (ll) phosphate in a single replacement reaction. How many grams of lithium phosphate are produced from 4.22 mol of lithium?

163.2 g of Li₃PO₄ are made in the reaction

Explanation:

In first place we determine the reaction, to see stoichiometry.

The reactants are Li and Pb₃(PO₄)₂; the products are Li₃PO₄ and Pb

Equation:  6Li + Pb₃(PO₄)₂ → 2Li₃PO₄ + 3Pb

6 moles of Li can produce 2 moles of lithium phosphate

Therefore, 4.22 moles of Li will produce (4.22 . 2) / 6 = 1.41 moles of Li₃PO₄

Let's convert the amount to mass, to find the

1.41 mol . 115.79 g / 1mol = 163.2 g

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml