If a 250 mL bag at 19°C, is
heated to 60°C, what will the
new volume of the bag be?

285.10mL

Explanation:

Using Charle's law

V1/T1 = V2/T2

T1=273+19=292K

T2=273+60=333

250/292=V2/333

V2=250×333/292

V2=285.10mL

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