How many grams of NaCl are needed to prepare 1.20 liters of a 2.00 M solution?
A) 70.2 g
B) 97.5 g
C) 117 g
D) 140 g

D) 140g

Explanation: no. of moles of NaCl = molarity X volume in litres = 2 X 1.2 = 2.4, and molar mass or mass of 1 mole of NaCl = 58.44 g, so 2.4 moles NaCl = 140.256 g

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.

i think its 100

i hope this !