At a certain temperature, the solubility of N2 gas in water at 4.07 atm is 95.7 mg of N2 gas/100 g water . Calculate the solubility of N2 gas in water, at the same temperature, if the partial pressure of N2 gas over the solution is increased from 4.07 atm to 10.0 atm .

Thus the solubility of gas in water, at the same temperature, if the partial pressure of gas is 10.0 atm is 235mg/100g.

Explanation:-

The Solubility of in water can be calculated by Henry’s Law. Henry’s law gives the relation between gas pressure and the concentration of dissolved gas.

Formula of Henry’s law,  .

= Henry’s law constant = ?

The partial pressure (P) of in water = 4.07 atm

\

At pressure of 10.0 atm

Thus the solubility of gas in water, at the same temperature, is 235mg/100g

look at the !

pleaze mark brainliest!

your answer would be a. 12.5 kg