The explosive nitroglycerin (C3H5N3O9) decomposes rapidly upon ignition or sudden impact according to the following balanced equation:

4C3H5N3O9(l)→12CO2(g)+10H2O(g)+6N2( g)+O2(g) ΔH∘rxn=−5678kJ

Required:
Calculate the standard enthalpy of formation (ΔH∘f) for nitroglycerin.

Explanation:

Hello,

For the given reaction, the standard enthalpy of reaction is:

As long as the both nitrogen's and oxygen's standard enthalpies of formation are 0, thus, by looking for water's and carbon dioxide's standard enthalpies of formation, we compute the standard enthalpy of formation for nitroglycerin as shown below:

Best regards.

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.