12.5ml of 2.0m NaOH neutralizes 10ml og HCL, what is the acid concentration

2.5M

Explanation:

We begin by writing a balanced equation for the reaction. This is shown below:

HCl + NaOH —> NaCl + H2O

From the equation above we obtained the following:

nA (mole of the acid) = 1

nB (mole of the base) = 1

Data obtained from the question include:

Vb (volume of the base) = 12.5mL

Mb (Molarity of the base) = 2M

Va (volume of the acid) = 10mL

Ma (Molarity of the acid) =?

The molarity of the acid can be calculated as follow:

MaVa/MbVb = nA/nB

Ma x 10 / 2 x 12.5 = 1

Cross multiply to express in linear form as shown below:

Ma x 10 = 2 x 12.5

Divide both side by 10

Ma = (2 x 12.5) /10

Ma = 2.5M

The molarity of the acid is 2.5M

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.

a electronegativity decreases beacuse the size of nucleus is bigger.