How much heat is released when 345 g of tin is cooled from 210.0 degrees * C to 0.0 C? (C= 0.220 J/gC)

18634 joules

Explanation:

The quantity of Heat Energy (Q) released when a heated substance is cooled depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = ?

Mass of oil = 345g

C = 0.220 J/g°C

Φ = (Final temperature - Initial temperature)

= 0°C - 220°C = -220°C

Then, Q = MCΦ

Q = 345g x 0.220 J/g°C x -220°C

Q = 18634 joules (note that negative sign will not reflect in answer, because it only indicates that heat was released rather than gained)

Thus, 18634 joules of heat is released

the only liquid elements at standard temperature and pressure are bromine (br) and mercury (hg). although, elements caesium (cs), rubidium (rb), francium (fr) and gallium (ga) become liquid at or just above room temperature.

explanation:

c is the answer because when something is left after something evaporates that shows the chemical change.