Consider the vaporization of liquid water to steam at a pressure of 1 atm. Part A Is this process endothermic or exothermic? Is this process endothermic or exothermic? endothermic exothermic Request Answer Part B In what temperature range is it a spontaneous process? In what temperature range is it a spontaneous process? below 100 ∘C above 100 ∘C below 0 ∘C above 0 ∘C at no temperature Request Answer Part C In what temperature range is it a nonspontaneous process? In what temperature range is it a nonspontaneous process? below 100 ∘C above 100 ∘C below 0 ∘C above 0 ∘C at no temperature Request Answer Part D At what temperature are the two phases in equilibrium? T T = nothing ∘C

Vaporization is an endothermic process which is spontaneous above 100∘C and not spontaneous below 100∘C. The liquid and gas phase of water are at equilibrium at 100∘C.

Vaporization of water refers to the conversion of liquid water to gaseous water. The process is endothermic because heat is taken in to break the intermolecular forces in liquid water as it is being converted to gas.

The process is sponteanous above 100∘C which is boiling point of water. At this temperature, the intermolecular interactions in water are broken. The process is not spontaneous below 100∘C.

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The answers to the questions are;

Part A, endothermic

Part B, above 100 °C

Part C below 100 °C

Part D, 100 °C.

Explanation:

Part A endothermic,

The vaporization of water requires the addition of the heat of vaporization for the given mass of water as well as the heat required to raise the water to the boiling point.

Part B, above 100 °C

The boiling or vaporization of water is a spontaneous process above the boiling point for water which is 100 °C point

Part C below 100 °C

It is a non-spontaneous process below the boiling point of water which is 100 °C

Part D, 100 °C

Water is in equilibrium with steam at 100 °C.

the answer would be b i believe