The highest pressure allowed in a detector allowed is 1.88kPa. How many atm (atmospheres) of pressure are in this?

0.0186 atm

Explanation:

Pressure can be measured in the following units: Pascals (pa), atmosphere (Atm), Newton per metre square (Nm^-2).

In this case,

Pressure of detector = 1.88kPa

(Covert 1.88kPa to Pascal)

Recall that 1kPa = 1000Pa

1.88kPa = 1.88 x 1000 = 1880Pa

Now, convert 1880Pa to Atm

Recall that:

1 Atm = 101325 pascal (Pa).

Z Atm = 1880Pa

To get the value of Z, cross multiply

1880Pa x 1 Atm = 101325Pa x Z Atm

1880 = 101325Z

Divide both sides by 101325

1880/101325 = 101325Z/101325

0.0186 = Z

Thus, the 0.0186 atm (atmospheres) of pressure in 1.88kPa

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.  

10 years is the answer