Study the balanced equation.

3Hg(OH)2 + 2H3PO4 → Hg3(PO4)2 + 6H2O

How many mols of phosphoric acid (H3PO4) reacted to form 3.13 x 101 mol of water (H2O)?

A) 5.22 × 100 mol H3PO4

B) 9.39 × 101 mol H3PO4

C) 6.26 × 101 mol H3PO4

D) 1.04 × 101 mol H3PO4

D) 1.04 × 10¹ mol H₃PO₄

Explanation:

Based on the reaction:

3Hg(OH)₂ + 2H₃PO₄ → Hg₃(PO₄)₂ + 6H₂O

2 moles of phosphoric acid produce 6 moles of water. If there are produced 3.13x10¹ moles of water, the phosphoric acid moles that reacted are:

3.13x10¹ moles of water ₓ (2 moles phosphoric acid / 6 moles of water) =  1.04 × 10¹ mol H₃PO₄

Right answer is:

D) 1.04 × 10¹ mol H₃PO₄

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