Aqueous solutions of sulfuric acid and sodium hydroxide can neutralize each other to produce a compound that is soluble in water. Give the chemical formulas of the anion and cation found in this compound.

Cation = Na⁺

Anion = SO₄²⁻

Compound = Na₂SO₄  

Explanation:

The reactions between sulfuric acid and sodium hydroxide are the following:        

H₂SO₄(aq) + Na⁺(aq) + OH⁻(aq)  ⇄  HSO₄⁻(aq) + Na⁺(aq) + H₂O(l)    (1)

HSO₄⁻(aq) + Na⁺(aq) + OH⁻(aq)  ⇄  SO₄²⁻(aq) + Na⁺(aq) + H₂O(l)     (2)

The net equation is:

H₂SO₄(aq) + 2NaOH(aq)  ⇄  Na₂SO₄(s) + 2H₂O(l)             (3)

Hence, from equation (3):  

Cation = Na⁺

Anion = SO₄²⁻

Compound = Na₂SO₄  

I hope it helps you!    

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890